Respuesta :
To solve this we need to have knowledge of experimental rate law which relates the rate to the concentration raise to some power. Therefore, the rate law for the iodine-clock reaction is Rate=k[H[tex]_2[/tex]O[tex]_2[/tex]][I⁻] and unit of rate constant is L/mol/s.
What is rate law?
A rate law represents the rate of a reaction . According to this rate is directly proportional to the concentration of reactants. There is another expression of rate law which is integrated rate law which is just opposite of differential rate law.
A traditional chemical clock display experiment to show reaction kinetics in action is the iodine clock reaction.
H[tex]_2[/tex]O[tex]_2[/tex]+2I⁻−+2H⁺⟶I[tex]_2[/tex]+2H[tex]_2[/tex]O
Rate=k[H[tex]_2[/tex]O[tex]_2[/tex]][I⁻]
unit of rate constant is L/mol/s.
Therefore, the rate law for the iodine-clock reaction is Rate=k[H[tex]_2[/tex]O[tex]_2[/tex]][I⁻] and unit of rate constant is L/mol/s.
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