A pitot tube (the figure) is used to determine the airspeed of an airplane. It consists of an outer tube with a number of small holes B (four are shown) that allow air into the tube; that tube is connected to one arm of a U-tube. The other arm of the U-tube is connected to hole A at the front end of the device, which points in the direction the plane is headed. At A the air becomes stagnant so that VA = 0, At B, however, the speed of the air presumably equals the airspeed B of the plane. Use Bernoulli's equation to derive a formula giving the air speed in terms of the difference h in the liquid levels in that tube, the density rho of the liquid in the U-tube, and the density of air Pair. Suppose that the tube contains alcohol and the level difference h is 34.0 cm. What is the plane's speed relative to the air? The density of the air is 1.14 kg/m3 and that of alcohol is 810 kg/m3. Air Hole A Liquid Number Units

Respuesta :

The plane's speed relative to the air is 63.3m/s.

What is relative speed?

When two or more bodies (objects) travel at the same or different speeds in the same or different directions, the concept of relative speed is applied. As a result, relative speed can be defined as a concept that calculates the speed of one moving body in relation to another moving body traveling at the same speed.

For example, if two people are running in opposite directions, the relative speed of one of them to the other stationary body can be calculated because the bodies are moving in opposite directions at the same time. Thus, relative speed can be defined as the speed of a moving body in relation to another stationary body.

  • The difference between the bodies is calculated while calculating the relative speed of bodies moving in the same direction.

) Bernoulli's equation gives p A =p b+    1   ρ air  v²

​                                                                  2

However, △=p A −p B =ρgh

in order to balance the pressure in the two arms of the U-tube.

Thus ρgh= 1  ρ air v²

                  2

, or v =  √2ρgh

             √  ρ air

(b) The plane's speed relative to the air is

v= ρ air 2ρgh  =√2(810kg/m 3 )(9.8m/s 2 )(0.260m) =63.3m/s

                                √ 1.03kg/m³

Hence, the plane's speed relative to the air  is 63.3m/s.

To know more about relative speed from given link

https://brainly.com/question/17228388

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