The total moment of inertia of the system is [tex]\frac{1}{2} ML^{2} + \frac{2}{5} MR^{2} + M(L+R)^{2}[/tex].
Given a sphere is attached to a rod. Let the masses of both rod and sphere be M. Let, radius of sphere be R and length of rod be L.
Now,
The total moment of inertia of system is:
I (rod about end) + I (sphere about center) + Parallel axis contribution =
[tex]\frac{1}{2} ML^{2} + \frac{2}{5} MR^{2} + M(L+R)^{2}[/tex].
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