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n L-C circuit containing an 80.0-mH inductor and a 1.25-nF capacitor oscillates with a maximum current of 0.86 A. Calculate: (a) the maximum charge on the capacitor and (b) the oscillation frequency of the circuit. (c) Assuming the capacitor had its maximum charge at time t = 0, calculate the energy stored in the inductor after 2.50 ms of oscillation.

Respuesta :

Energy stored in the inductor after 2.50 ms of oscillation is 1/2*L*I^2 ˜19.6uJ

What is Oscillation?

The process of any quantity or measure fluctuating repeatedly about its equilibrium value in time is known as oscillation.

The mechanical oscillations of an item are referred to as vibrations. But oscillations also happen in dynamic systems, or better said, in every branch of research. Even the heart's pounding causes oscillations. Oscillators, on the other hand, are things that move about an equilibrium point.

f = 1/2*p*vL*C

L = 80mH C = 1.25nF

f = 15.92KHz is the resonant frequency

given the maximum current = I = 0.75A

so,,max energy = 1/2L*I^2 = 22.5mJ

but,,it will be equal to max energy stored in capacitor =1/2*q^2/C

so,,maximum charge =q =v2* 22.5*10^-3*C =7.5uC

not sure about third part of the problem,,will find soon

here is the third part

I(t) = -w*Qmaxsin(wt+f)

f can be assumed to 0.

Qmax = 7.5uC

w = 2*p*f ˜100*10^3 and t = 2.5mSec

so,, I(t) = -100*7.5*10^-6 * (-0.94) = 0.7mA

so,,energy = 1/2*L*I^2 ˜19.6uJ

Learn more about Oscillation from given link

https://brainly.com/question/12622728

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