The potential difference is: a*ln(p2/p1).
The amount of work energy needed to move a unit of electric charge from a reference point to the specific point in an electric field is called electric potential.
We know that potential difference is given by formula:
[tex]V_{A} -V_{B} = \int\limits^b_a {E} \, ds[/tex]
where,
[tex]V_{A}- V_{B} =[/tex] Potential difference
E = Electric field
Given E = a/s , where a = constant
We have to find potential difference between point p1 and p2 (a = p1 and b = p2)
i.e. we need to find [tex]V_{p1} -V_{p2} = V[/tex]
Putting these values in above equation we get,
[tex]V = \int\limits^b_a {E/s} \, ds[/tex]
[tex]V = a log(b/a)\\V = alog(p2/p1)[/tex]
So the potential difference is: a*ln(p2/p1).
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