The probability that every even number appears at least once before the first occurrence of an odd is 1/20.
Given:
A fair 6-sided die is repeatedly rolled until an odd number appears.
There are 6! ways to order the 6 numbers and 3!(3!) ways to order the evens in the first three spots and the odds in the next three spots.
so the probability = 3!*3! / 6!
= 3!*3! / 6*5*4*3!
= 3*2*1 / 6*5*4
= 6*1 / 30*4
= 6/120
= 1/20
Therefore the probability that every even number appears at least once before the first occurrence of an odd is 1/20.
Learn more about the probability here:
https://brainly.com/question/11234923
#SPJ4
