Respuesta :
1. Kc value:
C. remains the same.
2. Qc value:
C. remain the same.
3. The reaction is:
B. Qc < Kc, the reaction will move in the forward direction.
4. The concentration of N2 is:
A. increase.
Whilst the awareness of all of the reactants increases extra molecules or ions interact to form new compounds and the fee of reaction increases. while the attention of a reactant decreases, there are fewer of that molecules or ions present, and the rate of reaction decreases. If the concentration of reactants is multiplied, there are more reactant particles moving collectively.
Calculation:-
Removing product will shift the reaction in the direction of product as per Le chatelier Principle
So, Equilibrium moves to product side
Since temperature is not changing Kc would not change.
B)Since we are removing product and Qc = [product]/[recatant]
Value of Qc will decrease and hence Qc will be less than Kc
C)Since Qc < Kc, the reaction will move in forward direction.
D)O2 is product here and reaction is moving towards product.
So, concentration of O2 would increase.
There could be more collisions and so the reaction charge is multiplied. The higher the awareness of reactants, the faster the fee of a response will be. awareness can be improved by means of dissolving an extra solute in a given extent of a solution this will increase the mass of the solute. awareness may be accelerated by means of permitting some of the solvents to evaporate this decreases the extent of the solution.
Learn more about Equilibrium here:-https://brainly.com/question/517289
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