The molecular mass of the unknown compound found in the aqueous solution was 223.2g/mol
The sum of the atomic masses of all atoms in a molecule is called as molecular weight
So to get molar mass of the compound from the given weight the concentration of compound is elucidated and thereby leading to the calculation of molar mass
Then the concentration of solute in an aqueous solution can be derived from the osmotic pressure equation
So the osmotic pressure = van't hoff factor then the molarity of solute(M) gas constant(R) temprature(T)
From the given values in the question and applying constant values
8.44 torr = 1(for non electrolytes)× M×62.3637L⁻¹torr⁻¹mol⁻¹×298K
M = 4.54×10⁻⁴M
From the molarity of the given compound the molare mass can be calculated as
Molarity = weight/ molecular weight × 1000/volume(ml)
4.54×10⁻⁴M = 0..0152g/molecular weight × 1000/150ml)
Molecular weight = 223.2g/mol
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