Probability that the coin lands heads exactly 11 times is 0.1602 so Option a is correct.
Given:
an unbiased coin is tossed 20 times.
The probability that the coin lands heads exactly 11 times:
P = n(E)/n(S)
n(S) = 2^tosses
= 2^20
= 1048576
n(E) = C(20,11)
= 20!/11!(20-11)!
= 20!/11!*9!
= 167960
Probability P = 167960/1048576
= 0.16017 ≈ 0.1602
Therefore Probability that the coin lands heads exactly 11 times is 0.1602 so Option a is correct.
Learn more about the probability here:
https://brainly.com/question/11234923
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