you have 8 batteries sitting on your desk, 3 of which are dead. your calculator requires 2 good batteries to function. If you select 2 batteries at random, what is the probability your calculator will not function
Let x be the case that calculator Does function. x' means it will not function. Then P(x') = 1 - P(x)
Its easier to find P(x) since it requires that both batteries are good. There are 3 dead batteries and 5 good ones. P(x) can be found by dividing at the combinations which gives 2 good batteries by total combinations.
