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All the circles are similar.
That is because you can transform one circle onto another by two similarity operations: translation and dilation (scale factor).
For these two circles you have to translate the center of circle 1 to the center of circle 2, which will make that the two circles are concentric (have the same center).
The two centers are (-6,2) and (-1,- 4). To move the center (-6, 2) to (-1,4) you have to shift it 5 units to the right and 6 units down:
-6 + 5 = -1
2 - 6 = - 4.
After this translation, you dilate the circle with smaller radius using a scale factor equal to the ratio of the bigger radius to the smaller radius: 8/6 = 4/3.
Enter the scale factor as a fraction in simplest form. ----> 4/3
The circles are similar because the transformation rule (+5 , - 6) can be applied to Circle 1 and then dilate it using a scale factor of 4/3.
That is because you can transform one circle onto another by two similarity operations: translation and dilation (scale factor).
For these two circles you have to translate the center of circle 1 to the center of circle 2, which will make that the two circles are concentric (have the same center).
The two centers are (-6,2) and (-1,- 4). To move the center (-6, 2) to (-1,4) you have to shift it 5 units to the right and 6 units down:
-6 + 5 = -1
2 - 6 = - 4.
After this translation, you dilate the circle with smaller radius using a scale factor equal to the ratio of the bigger radius to the smaller radius: 8/6 = 4/3.
Enter the scale factor as a fraction in simplest form. ----> 4/3
The circles are similar because the transformation rule (+5 , - 6) can be applied to Circle 1 and then dilate it using a scale factor of 4/3.
The circles are similar because the transformation rule (x + 5, y - 6) can be applied to Circle 1 and then dilate it using a scale factor of 0.75
The given parameters are:
Circle 1
- Radius = 8 cm
- Center = (-6,2)
Circle 2
- Radius = 6 cm
- Center = (-1,-4)
Because the radii and the centers of both circles are not the same;
Then, the circles can be proved to be similar by translating and dilating either circles
Divide the radius of circle 2 by the radius of circle 1, to calculate the scale factor (k)
[tex]k = \frac{6cm}{8cm}[/tex]
[tex]k = 0.75[/tex]
Also, the translation rule is calculated as follows:
[tex](x_1,y_1) - (x,y) = (x_2,y_1)[/tex]
So, we have:
[tex](-6,2) - (x,y) = (-1,-4)[/tex]
Collect like terms
[tex](x,y) = (-6--1,2--4)[/tex]
[tex](x,y) = (-5,6)[/tex]
Hence, the circles are similar because the transformation rule (x + 5, y - 6) can be applied to Circle 1 and then dilate it using a scale factor of 0.75
Read more about transformation at:
https://brainly.com/question/10676099