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A set of numbers is shown below: {0, 0.6, 2, 4, 6} Which of the following shows all the numbers from the set that make the inequality 2x + 3 ≥ 7 true?

Respuesta :

AbhiGhost
The given equality hold true when x = 2.

Put x = 2 in inequality.

2(2) + 3 = 4+3 = 7 = R.H.S.

For x = 4 and 6, L.H.S(2x+3) is greater than 7.

Hence for x = 2, 4 and 6, the above inequality holds true.

Hope this helps!

Answer:

2,4,and 6 are the numbers that show the inequality

2×2+3=7

4×2+3>7

6×2+3>7

Step-by-step explanation:

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