Answer:
[tex]\csc ^2(\theta)[/tex]
Step-by-step explanation:
Using Pythagorean identity,
[tex]\mathrm{1+\cot ^2(x)=\csc ^2(x)}\\\mathrm{=\csc ^2(\theta)}[/tex]
1 + cot² θ = sec² θ
1 + cot²θ =
I know this identity to be true:
sin² θ + cos² θ = 1
Divide both sides by sin² θ.
sin² θ / sin² θ + cos² θ / sin² θ = 1 / sin² θ
