The average temperature in the mountains is 65° in April. The average temperature in that same spot is −5° in December. Determine how much warmer this location is in April than in December, and determine which temperature is the farthest away from 0°.\

65 + |−5| = 70°, 65° is the farthest from 0°
65 − |−5| = 60°, 65° is the farthest from 0°
65 + |−5| = 70°, −5° is the farthest from 0°
65 − |−5| = 60°, −5° is the farthest from 0°

Respuesta :

Option A, 65 + |−5| = 70°, 65° is the farthest from 0°

Here, we are given that.

The average temperature in the mountains is 65° in April.

The average temperature in that same spot is −5° in December.

Thus, the difference in the temperature will be-

65 - (-5)

= 65 + 5

= 70°

Therefore, this location is 70° warmer in April than in December.

Now, their distance from 0 will be-

|65 - 0| = 65

as distance cannot be negative, we look at only the absolute difference.

Similarly |-5 -0| = 5

Thus, we see that 65° is the farthest from 0°.

Hence, option A, 65 + |−5| = 70°, 65° is the farthest from 0°, is the correct answer.

Learn more about the absolute value function here-

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