Answer:
c.) 6√3
Step-by-step explanation:
This can be solved using both sine and cosine rule.
1st method:
[tex]\sf sin(x) = \dfrac{opposite}{hypotenuse}[/tex]
[tex]\sf sin(60) = \dfrac{long \ leg}{12}[/tex]
[tex]\sf long \ leg= 12sin(60)[/tex]
[tex]\sf long \ leg= 6\sqrt{3}[/tex]
2nd method:
[tex]\sf cos(x) = \dfrac{adjacent}{hypotenuse}[/tex]
[tex]\sf cos(30) = \dfrac{long \ leg}{12}[/tex]
[tex]\sf long \ leg= 12cos(30)[/tex]
[tex]\sf long \ leg=6\sqrt{3}[/tex]
