Answer:
y = -2
Step-by-step explanation:
Given equation:
[tex]3(-4y-5)=8y+25[/tex]
Distribute:
[tex]\implies 3 \cdot -4y - 3 \cdot 5=8y+25[/tex]
[tex]\implies -12y - 15=8y+25[/tex]
Add 15 to both sides:
[tex]\implies -12y - 15+15=8y+25+15[/tex]
[tex]\implies -12y =8y+40[/tex]
Subtract 8y from both sides:
[tex]\implies -12y-8y =8y+40-8y[/tex]
[tex]\implies -20y =40[/tex]
Divide both sides by -20:
[tex]\implies \dfrac{-20y}{-20} =\dfrac{40}{-20}[/tex]
[tex]\implies y =-2[/tex]
