angle POR and angle ROQ from linear pair . If a-b=
[tex] {80}^{0} [/tex]
find the value a and b .

Answer:
a = 130
b = 50
Explanation:
Analyze that the angles a and b lies on a straight line summing up to 180°.
Equation's:
make 'a' subject in eq 1
a + b = 180
a = 180 - b
substitute this into eq 2
a - b = 80
(180 - b) - b = 80
180 - 2b = 80
-2b = 80 - 180
-2b = -100
b = 50
Find value of 'a':
a = 180 - b
a = 180 - 50
a = 130
Answer:
a = 130°, b = 50°
Step-by-step explanation:
The given equation is,
→ a - b = 80°
→ a + b = 180°
The equation we form is,
→ (a + b) + (a - b) = 180 + 80
Now the required value of a will be,
→ (a + b) + (a - b) = 180 + 80
→ (a + a) + (b - b) = 260
→ 2a = 260
→ a = 260/2
→ [ a = 130° ]
Hence, the value of a is 130°.
Then the required value of b will be,
→ a + b = 180
→ 130 + b = 180
→ b = 180 - 130
→ [ b = 50° ]
Hence, the value of b is 50°.