Answer: sinW≈0.75
Step-by-step explanation:
[tex]m\angle X=90^0\ \ \ \ XV=48\ \ \ \ \ WV=73\ \ \ \ \ VX=55\ \ \ \ sinW=?[/tex]
The sine theorem: The sides of a triangle are proportional to the sines of the opposing angles
Hence,
[tex]\displaystyle\\\frac{WV}{sinX} =\frac{VX}{sinW} \\\\\frac{73}{sin90^0} =\frac{55}{sinW} \\\\\frac{73}{1} =\frac{55}{sinW} \\\\sinW=\frac{55}{73} \\\\sinW\approx0.75[/tex]
