Answer:
38.3 m/s
Explanation:
To find vertical component of initial velocity, you'd have to use sine ratio:
[tex]\displaystyle{\sin \theta = \dfrac{u_y}{u}}[/tex]
[tex]\displaystyle{u_y}[/tex] is vertical component of initial velocity and [tex]\displaystyle{u}[/tex] is initial velocity given which is 50 m/s.
A stone is projected at an angle of 50 degrees so [tex]\displaystyle{\theta}[/tex] = 50°. Substitute in the formula:
[tex]\displaystyle{\sin 50^{\circ} = \dfrac{u_y}{50}}\\\\\displaystyle{50 \sin 50^{\circ} = u_y}\\\\\displaystyle{u_y = 38.3 \ \, \sf{m/s}}[/tex]
Therefore, the vertical component of initial velocity is approximately 38.3 m/s
(The picture is also attached for visual reference!)
