The volume of water in the first tank is 3,125 m³
How to find the volume of water in the smallest cylinder?
Assuming that the two cylinders are similar, we know that the relation between the surfaces areas is given by:
A₂ = k²*A₁
That says "the area of the larger cylinder is k² times the area of the smaller cylinder"
Where k is the scale factor between the two cylinders.
From that, we also can relate the volumes by:
V₂ = k³*V₁
First, we know that the areas are 50m² and 162m², with that we can get the value of k.
162m² = k²*50m²
k² = (162/50) = 3.24
k = √3.24 = 1.8
Then the relation between the volumes is:
V₂ = (1.8)³*V₁
And we know that:
V₂ = 36450m³
Then we can write:
V₁ = (36,450m³)/( (1.8)³ ) = 6,250 m³
That is the total volume of the smaller cylinder, but we know that it is half full, then the volume of water in that cylinder is:
V = (6,250 m³)/2 = 3,125 m³
The volume of water in the first tank is 3,125 m³
If you want to learn more about cylinders:
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