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A caterer needs 12 workers for an event, but 5% of workers generally do not show up. The caterer wants at least a 90% probability that enough workers show up, so she hires 13 workers. Is this a good strategy? What is the probability that enough workers show up?

Respuesta :

Using the binomial distribution, it is found that this is not a good strategy, as the probability that enough workers show up is below 90%.

What is the binomial distribution formula?

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, the values of the parameters are given by:

n = 13, p = 0.95.

The probability that at least 12 workers show up is:

P(X >= 12) = P(X = 12) + P(X = 13)

Applying the binomial distribution formula, we have that:

  • P(X = 12) = 13 x (0.95)^12 x 0.05 = 0.3512.
  • P(X = 13) = (0.95)^13 = 0.5133.

Then, the probability that enough workers show up is given by:

P(X >= 12) = P(X = 12) + P(X = 13) = 0.3512 + 0.5133 = 0.8645 = 86.45%.

This is not a good strategy, as the probability that enough workers show up is below 90%.

More can be learned about the binomial distribution at https://brainly.com/question/24863377

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