The length of A"B" is 20 units
How to determine the length of A'B'?
From the figure, we have:
A = (1, 4)
B = (4, 8)
The distance AB is:
[tex]AB = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]
So, we have:
[tex]AB = \sqrt{(1 -4)^2 + (4-8)^2[/tex]
Evaluate
[tex]AB = \sqrt{25[/tex]
This gives
AB = 5
The scale factor of dilation is 4.
So, we have:
A'B' = 5 * 4
Evaluate
A'B' = 20
Hence, the length of A"B" is 20 units
Read more about dilation at:
https://brainly.com/question/18977334
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