The equation of the line is: y + 3 = -6(x + 2) [point-slope form] or y = -6x - 15 [slope-intercept form].
Given a point (-2, -3) and a slope (m) of -6, you can write the equation of the line in point-slope form by substituting (a, b) = (-2, -3) and m = -6 into y - b = m(x - a):
y - (-3) = -6(x - (-2))
y + 3 = -6(x + 2) [point-slope form]
Rewrite in slope-intercept form as:
y + 3 = -6(x + 2)
y + 3 = -6x - 12
y = -6x - 12 - 3
y = -6x - 15 [slope-intercept form]
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