Jon is filling the tub at a rate of 0.5 ft3/min is 0.3125 ft/min.
If we take a look at a rectangular bathtub, the volume of the bathtub can be expressed as:
Volume (V) = length × breadth × height
where;
the base = length × breadth = 16ft²
∴ the volume of the rectangular bathtub = 16h --- (1)
Using differentiation to differentiate 16h with respect to t implicitly, then:
dV/ dT = 16 dH /dT
When the rate of rising of the volume is 0.5 ft³/min
Then:
0.5 = 16 dH /dT
dH /dT = 1 / 16 * 0.5
dH /dT = 0.3125.
Jon is filling the tub at a rate of 0.5 ft3/min is 0.3125 ft/min.
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