If you started with 2.864 g of sodium bicarbonate and heated it to constant mass, 0.59 gram would be the mass that residue after the reaction.
Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now we have to write the balanced equation
2NaHCO₃ → Na₂CO₃ + CO₂ + H₂O
According to Stoichiometry
= [tex]2.864\ g\ NaHCO_{3} \times \frac{1\ \text{mole}\ Na_2CO_3}{105.9\ g/mol} \times \frac{1\ \text{mole}\ CO_2}{2\ \text{mole}\ NaHCO_3} \times \frac{44\ g \ CO_2}{1\ \text{mole}\ CO_2}[/tex]
= 0.59 g
Thus from the above conclusion we can say that If you started with 2.864 g of sodium bicarbonate and heated it to constant mass, 0.59 gram would be the mass that residue after the reaction.
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Question: If you started with 2.486 g of sodium bicarbonate and heated it to constant mass, what would the mass of the residue be after the reaction? Show your work.
NaHCO₃ → Na₂CO₃ + CO₂ + H₂O
