In a sample consisting of 2.50 g of methane (CH4), there are 4.5 × 10²³ atoms present.
To calculate the number of moles it is expressed as
Number of moles = [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
= [tex]\frac{2.50\ g}{16\ g/mol}[/tex]
= 0.15 mol
1 mole of methane contains 6.022 × 10²³ molecules
0.15 mole of methane will contain
= [tex]\frac{0.15 \times 6.022 \times 10^{23}}{1}[/tex]
= 0.9 × 10²³ molecules
= 0.9 × 10²³ × 5 atoms
= 4.5 × 10²³ atoms of methane
Thus from the above conclusion we can say that In a sample consisting of 2.50 g of methane (CH4), there are 4.5 × 10²³ atoms present.
Learn more about the Number of moles here: https://brainly.com/question/13314627
#SPJ4
