When an electron in an atom absorbed a photon, the energy of the electron changed by 2.94 × 10⁻¹⁹. The frequency of the photon is 4.4 × 10¹⁴ Hertz .
How to calculate the frequency of photon ?
To calculate the frequency of photon use the expression
E = hv
where,
E = Energy
h = Planck's Constant
v = frequency (Hz)
Put the value in above formula we get
E = hv
2.94 × 10⁻¹⁹ = 6.6 × 10⁻³⁴ × v
v = [tex]\frac{2.94 \times 10^{-19}\ J}{6.6 \times 10^{-34}}[/tex]
= 0.44 × 10¹⁵
= 4.4 × 10¹⁴
Thus from the above conclusion we can say that When an electron in an atom absorbed a photon, the energy of the electron changed by 2.94 × 10⁻¹⁹. The frequency of the photon is 4.4 × 10¹⁴ Hertz .
Learn more about the Plank's Constant here: https://brainly.com/question/27163891
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