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A person walks first at a constant speed of 5.00 m.s-1
along a straight line from point A to
point B and then back along the line from B to A at a constant speed of 3.00 m.s-1
.
(a) Calculate her average speed over the entire trip.

Respuesta :

onyebuchinnaji

The average speed of the person over the entire trip is 3.75 m/s.

Average speed of the person

Average speed = total distance/total time

Average speed = (d + d)/(d/Va + d/Vb)

where;

  • d is the distance in a single trip
  • Va is speed from point A
  • Vb is the speed from point B

Average speed = (2Vavb)/(Va + Vb)

Average speed = (2 x 5 x 3)/(5 + 3)

Average speed = 3.75 m/s

Thus, the average speed of the person over the entire trip is 3.75 m/s.

Learn more about average speed here: https://brainly.com/question/6504879

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