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8. Assuming the density of your initial acid solution is 1.0 g/mL, what is the concentration (in molarity) of the diluted acetic acid, [CH3COOH], solution

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okpalawalter8

Assuming the density of your initial acid solution is 1.0 g/mL.  the concentration (in molarity)  is mathematically given as

M= 0.75 M

What is the concentration (in molarity) of the diluted acetic acid, [CH3COOH], solution?

Generally, the equation for Molarity  is  mathematically given as

M= (W/MW) ×1000

Therefore

[tex]M= (\frac{4.5} {60.05} \frac{(1000}{ 100}[/tex]

M = 0.75 M

In conclusion, The initial molarity  is given by

M= 0.75 M

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