55.2218 grams of magnesium chloride must be added to 725 mL of water to create a solution with an anion concentration equal to 0.800 M.
To calculate the number of moles from molarity as
[tex]\frac{\text{x moles}\ MgCl_2}{0.725\ \text{L solution}} = \frac{0.8\ \text{moles}\ MgCl_2}{1.0\ \text{L solution}}[/tex]
x moles MgCl₂ = [tex]\frac{0.8\ \text{moles}\ MgCl_2}{1.0\ \text{L solution}} \times 0.725\ \text{L solution}[/tex]
= 0.58 moles MgCl₂
Mass of one mole of substance is known as molar mass.
Molar mass of MgCl₂ = Atomic mass of Mg + 2 (Atomic mass of Cl)
= 24.31 + 2 (35.5)
= 95.21
Convert moles to grams
0.58 moles MgCl₂ × [tex]\frac{95.21\ g}{1\ \text{mole}\ MgCl_2}[/tex]
= 55.2218 grams
Thus from the above conclusion we can say that 55.2218 grams of magnesium chloride must be added to 725 mL of water to create a solution with an anion concentration equal to 0.800 M.
Learn more about the Molar mass here: https://brainly.com/question/837939
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