Respuesta :
69 gram PCl₅ will be produced from the given masses of both reactants that is 28.0 g of P₄ and 59.0 g of Cl₂.
What is Balanced Chemical Equation ?
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now we have to write the balanced equation
P₄ + 10Cl₂ → 4PCl₅
How to calculate the number of moles ?
To calculate the number of moles used the formula
Number of moles = [tex]\frac{\text{Given Mass}}{\text{Molar mass}}[/tex]
Number of moles of P₄ = [tex]\frac{\text{Mass of}\ P_4}{\text{Molar mass of}\ P_4}[/tex]
= [tex]\frac{28\ g}{124\ g/mol}[/tex]
= 0.225 mol
Number of moles of Cl₂ = [tex]\frac{\text{Mass of}\ Cl_2}{\text{Molar mass of}\ Cl_2}[/tex]
= [tex]\frac{51\ g}{71\ g/mol}[/tex]
= 0.831 mol
From the balanced chemical equation we can say that the ratio of P₄ and Cl₂ is 1 : 10.
Ratio of P₄: 0.2260: 1 = 0.2260
Ratio of Cl₂: 0.8310: 10 = 0.08310
Because ratio of Cl₂ ratio smaller than P₄ becomes the limiting reactants
So mole of PCl₅ is based on mole of Cl₂
From the coefficient of reaction:
mol PCl₅: mol Cl₂ = 4: 10
Mole of PCl₅ = [tex]\frac{4}{10} \times 0.8310[/tex]
= 0.3324
Molar mass of PCl₅= 208.5
Mass of PCl₅ = mole × molar mass
Mass of PCl₅ = 0.3324 × 208.5
Mass of PCl₅ = 69 gram
Thus from the above conclusion we can say that 69 gram PCl₅ will be produced from the given masses of both reactants that is 28.0 g of P₄ and 59.0 g of Cl₂.
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Question: What mass of PCl₅ will be produced from the given masses of both reactants that is 28.0 g of P₄ and 59.0 g of Cl₂ ?
69.3 gram PCl₅ will be produced from the given masses of both the reactants.
Balanced chemical equation is
P₄ + 10Cl₂ → 4PCl₅
Four moles of PCl₅ are produced by combining one mole of P₄ with ten moles of chlorine.
Given mass of P₄ = 28gm
Molecular mass of P₄ = 123.89 g/mole
No. of moles(P₄) = Given mass / Molar mass
=28/123.89 =0.226 moles …. (1)
Given mass of Cl₂ = 59gm
Molecular mass of Cl₂ = 70.906 g/mole
No. of moles of Cl₂ = 59/70.906 = 0.832 mole.... (2)
From the chemical equation
Ratio of moles of P₄ and Cl₂ is 1 : 10
Also, from equation (1) & (2)
Ratio of moles of P₄ and Cl₂ is 0.226 : 0.832
If we make the ratio 1 : 1 then,
Ratio of moles of P₄ and Cl₂ becomes 0.226 : 0.0832
As the ratio of moles of Cl₂ is less than moles of P₄ , So Cl₂ becomes the limiting reactant.
Hence, mole of PCl₅ can be estimated on the basis of moles of Cl₂
From the coefficient of reaction:
mole of PCl₅ : mole of Cl₂ = 4: 10
10 moles of Cl₂ produce 4 moles of PCl₅
O.832 moles of Cl₂ produce 0.3328 moles of PCl₅
Molecular mass of PCl₅= 208.5 g/mole
Mass of PCl₅ = No. of moles × molar mass
Mass of PCl₅ = 0.3328 × 208.5
Mass of PCl₅ = 69.3 gram
Thus from the above conclusion we can say that 69.3 gram PCl₅ will be produced from the given masses of both reactants that is 28.0 g of P₄ and 59.0 g of Cl₂.
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