The equilibrium concentration of ethyl acetate will be 5.39 M.
Initially, 8.59 M acetic acid react with 8.59 M ethanol.
acetic acid + ethanol ===> ethyl acetate + water
(8.59) (8.59) (0)
after some time, some change will happen.
acetic acid + ethanol ===> ethyl acetate + water
(8.59-x) (8.59-x) (x)
At equilibrium condition,
acetic acid + ethanol ===> ethyl acetate + water
(3.20) (3.20) (x)
At equilibrium, for acetic acid and ethanol to go from 8.59 to 3.20, the value of x must be 5.39.
Therefore, the equilibrium concentration of ethyl acetate will be 5.39 M.
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