If sec x° = five thirds, what is the value of b? triangle lmn in which angle m measures 90 degrees, angle l measures x degrees, ln measures 20 units, and lm measures 3b units b = 4 b = 5 b = 6 b = 7

Respuesta :

The correct answer is, b=4.

Given Information and To Find

It is given that in a right angled-triangle lmn,

∠m = 90°

∠l = x°

ln = 20 units

lm = 3b units

[tex]secx = \frac{5}{3}[/tex]

We have to find the value of b.

What is a right-angled triangle?

A right triangle is a triangle in which one of the angles is at a right angle or two of the sides are perpendicular, or more formally, an orthogonal triangle, formerly known as a right-angled triangle. Trigonometry's fundamental concept is the relationship between a right triangle's sides and other angles.

Applying Trigonometry

We know that in a right angled-triangle,

[tex]sec x=\frac{hypotenuse}{base}[/tex]

In this case, we have (refer to the diagram),

[tex]secx=\frac{ln}{lm}[/tex]

⇒ [tex]\frac{20}{3b} = \frac{5}{3}[/tex]

⇒ [tex]20(3) = 3b(5)[/tex]

⇒ [tex]15b = 60[/tex]

⇒ [tex]b=4[/tex]

Learn more about a right - angled triangle here:

https://brainly.com/question/3770177

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