If the population is in Hardy-Weinberg equilibrium, the genotype frequencies should be 0.49 AA, 0.42 Aa, and . 09 aa.
Frequency of genotypes "AA" and "Aa". The frequency of AA is equal to p2 and the frequency of Aa is equal to 2pq. Therefore, using the above information, the frequency of AA is 16% (that is, p2 is 0.4 x 0.4 = 0.16) and Aa is 48% (2pq = 2 x 0.4 x 0.6 = 0.48).
Scientists need to look at at least two generations to find out if the population is in Hardy-Weinberg equilibrium. If the allele frequency is the same for both generations, the population is in Hardy-Weinberg equilibrium.
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