A research scientist wants to know how many times per hour a certain strand of bacteria reproduces. The mean is found to be 7.6 reproductions and the population standard deviation is known to be 2.2. If a sample of 707 was used for the study, construct the 90% confidence interval for the true mean number of reproductions per hour for the bacteria. Round your answers to one decimal place.

Respuesta :

The confidence interval for the true mean number of reproductions per hour is (7.5,7.7)

Given mean of 7.6 , standard deviation of 2.2, n=707 and 90% confidence level.

We have to find the confidence interval for the true mean number of reproductions per hour for the bacteria.

α=0.90

μ=7.6

σ=2.2

m=707

α/2=0.45

We have to calculate z value for the p value of 0.45 which is z=1.64.

Margin of error=z*μ/[tex]\sqrt{n}[/tex]

=1.64*2.2/[tex]\sqrt{707}[/tex]

=0.13

Lower level=mean -m

=7.6-0.13

=7.47

after rounding upto 1 decimal

=7.5

Upper level= mean +m

=7.6+0.13

=7.73

after rounding upto 1 decimal

=7.7

Hence the confidence interval is (7.5,7.7) for the true mean number of reproductions per hour.

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