contestada

A swimming pool is shaped like the figure below. Each end is a semicircle, and the length and
width of the rectangle are 40 feet and 20 feet, respectively. If there were a -foot-wide cement
border around the pool, what would be the area of the border?

Respuesta :

onyebuchinnaji

The area of the border around the pool is determined as 145.97 ft².

Area of the pool

Diameter of the circle = 20 ft

Radius of the circle = 10 ft

Area of circular portion:

Area = π(10²) = 314.16 ft²

Area of rectangular portion

A = 40 ft x 20 ft = 800 ft²

Pool area = 314.16 ft² + 800 ft² = 1,114.16 ft²

Overall area which include 1 foot border

Diameter of the circle = 20 ft + 1ft + 1 ft = 22 ft

Radius of the circle = 11 ft

Area of circular portion:

A = π(11²) = 380.13 ft²

Area of rectangular portion:

A = 22 ft x 40 ft = 880 ft²

Total area = 880 ft² + 380.13 ft² = 1,260.13 ft²

Area of the border

Area of border = Total area - pool area

Area of border = 1,260.13 ft² - 1,114.16 ft²

Area of border = 145.97 ft²

Thus, the area of the border around the pool is determined as 145.97 ft².

Learn more about area of circle here: https://brainly.com/question/12269818

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