At a temperature of 11.5 °C the gas occupies a volume of 0.0141 m³. Calculate the volume the gas occupies when the temperature is raised to 95.0 °C. ​

Respuesta :

Taking into account the Charles's law, the gas occupies a volume of 0.0182 m³ when the temperature is raised to 95.0 °C. ​

Charles's law

Charles's law shows the relationship between the volume and temperature of a gas sample at constant pressure.

This law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles' law is a law that says that when the amount of gas and pressure remain constant, the ratio between volume and temperature will always have the same value:

[tex]\frac{V}{T}= k[/tex]

Considering an initial state 1 and an initial state 2:

[tex]\frac{V1}{T1}= \frac{V2}{T2}[/tex]

Volume in this case

In  this case, you know:

  • V1= 0.0141 m³
  • T1= 11.5 C= 284.5 K (being 0 C= 273 K)
  • V2= ?
  • T2= 95 C= 368 K

Replacing in Charles's Law:

[tex]\frac{0.0141 m^{3} }{284.5 K}=\frac{V2}{368 K}[/tex]

Solving:

[tex]\frac{0.0141 m^{3} }{284.5 K}x368 K=V2[/tex]

0.0182 m³= V2

Finally, the gas occupies a volume of 0.0182 m³ when the temperature is raised to 95.0 °C. ​

Learn more about Charles's law:

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