Find an equation of a line with slope -3/4 and that passes through P(-4,6) in standard, form.

Answer:
[tex]y = - \frac{3}{4}x + 3[/tex]
Step-by-step explanation:
the standard form of any straight line is:
y = m × x + c
where: y is the y value of the point
x is the x value of the point
m is the gradient/slope
SOLUTION
[tex]y = mx + c \\ 6 = - \frac{3}{4} ( - 4) + c \\ c = 3[/tex]