Which quadratic equation does not have a real solution? (1 point)
3x2 − 6x + 3 = 0
−4x2 − 4x − 6 = 0
−x2 − 6x − 9 = 0
2x2 − 10x − 5 = 0

Respuesta :

Since it has a negative discriminant, the quadratic equation that does not have a real solution is given by:

−4x2 − 4x − 6 = 0.

What is the discriminant of a quadratic equation and how does it influence the solutions?

A quadratic equation is modeled by:

[tex]y = ax^2 + bx + c[/tex]

The discriminant is:

[tex]\Delta = b^2 - 4ac[/tex]

The solutions are as follows:

  • If [tex]\mathbf{\Delta > 0}[/tex], it has 2 rational solutions.
  • If [tex]\mathbf{\Delta = 0}[/tex], it has 1 rational solutions.
  • If [tex]\mathbf{\Delta < 0}[/tex], it has 0 real solutions.

We want [tex]\Delta < 0[/tex], hence, for equation -4x² - 4x - 6, we have that a = -4, b = -4, c = -6, hence:

[tex]\Delta = (-4)^2 - 4(-4)(-6) = 16 - 96 = -80[/tex]

Negative discriminant, hence it does not have a real solution.

More can be learned about the discriminant of a quadratic function at https://brainly.com/question/19776811

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