Please help me with problem 3 (a-d). Thank you!

Using the spread sheet we can easily get the answers:
The statistical section helps find answers by putting the accurate formula or the graphing calculator.
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 1471.33 2 735.68 11.59 0.001072834 3.7389
Within Groups 888.55 14 63.4677
Total 2359.882 16
The APA style refers to Times New Roman Font 12 pts.
The effect size of the result is 0.6233 medium
Part A
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 1471.33 2 735.68 11.59 0.001072834 3.7389
Within Groups 888.55 14 63.4677
Total 2359.882 16
1) The null and alternative hypotheses are
H0: u1=u2=u3
Ha: Not all means are equal
2) The significance level is alpha = 0.05
3) The test statistic F = sb²/sw²
Which if H0 is true has an F distribution with ν1=2 and v2= 14 degrees of freedom.
The computations are
Anova: Single Factor
Groups Count Sum Average Variance
Column 1 6 373 62.16666667 78.96666667
Column 2 4 324 81 60.66666667
Column 3 7 402 57.42857143 51.95238095
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 1471.33 2 735.68 11.59 0.001072834 3.7389
Within Groups 888.55 14 63.46768707
Total 2359.882353 16
5) The critical region is F ≥ F(0.05)(2,14) = 3.74
6) Conclusion:
Since the computed value F= 3.73 does not fall in the critical region F> 3.74 so we accept H0 and conclude that there is no significant difference in the three means.
Part D: The effect size of the result is 0.6233 medium and calculated by
η²= ss between/ ss between + ss error
η²= 1471/1471+889
η²= 0.6233
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