The volume of morphine required to be added to a 500 mL bag of fluids to deliver 0.24 mg/kg/hr to a 15-lb. dog at a delivery rate of 20 mL/hr is 2.7 ml; option A.
The volume of morphine required is determined as follows:
Volume of fluid = 500 mL
Delivery rate = 20 mL/hr
Dose delivered per hour = 0.24 mg/kg body weight
weight of dog in kg = 6.8 kg
Amount of morphine required for the dog = 0.24 * 6.8 = 1.632 mg/hr
This amount should be present in 20 mL of the fluid
Amount in 500 mL = 1.632 mg * 500/20 = 40.8 mg
Concentration of morphine = 15 mg/mL
Volume of morphine required = 40.8/15 = 2.72 ml
In conclusion, 2.7 mL of the morphine is required.
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