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Calculate the relative rate of diffusion of 1H2 (molar mass 2.0 g/mol) compared with 2H2 (molar mass 4.0 g/ mol) and the relative rate of diffusion of O2 (molar mass 32 g/mol) compared with O3 (molar mass 48 g/mol).

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Answer:

The relative rate of diffusion of 1H2 compared with 2H2 can be calculated using Graham's law of diffusion:

Rate1H2/Rate2H2 = (M2/M1)^0.5

Rate1H2/Rate2H2 = (4.0/2.0)^0.5

Rate1H2/Rate2H2 = 2.0

This means that 1H2 diffuses at twice the rate of 2H2.

The relative rate of diffusion of O2 compared with O3 can be calculated using Graham's law of diffusion:

RateO2/RateO3 = (M3/M2)^0.5

RateO2/RateO3 = (48.0/32.0)^0.5

RateO2/RateO3 = 1.5

This means that O2 diffuses at 1.5 times the rate of O3.

Explanation:

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