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Use the scenario to answer the question.

Bryan is asked to find the interquartile range for the data set {5,6,6,8,10,11,14,16,17}.
His work follows.

Step A: Find the median of the data set. The median, or Q2, is 10.
Step B: Find the value of Q1, or the median of the lower half of the data set, {5,6,6,8}.

Q1=6+62=6

Step C: Find the value of Q3, or the median of the upper half of the data set, {11,14,16,17}.

Q3=14+162=15

Step D: Find the difference between Q3 and Q1.

IQR=15−6=9

At which step did Bryan make a mistake, if he made one?

At Step B, he incorrectly found the value of Q1. He should have found the sum of the values and then divided by 4 to get Q1=6.25.At Step B, he incorrectly found the value of textsf cap q 1. He should have found the sum of the values and then divided by 4 to get

At Step A, he incorrectly found the value of the median. He should not have included both 6 values, so the median is 10+112=10.5.At Step A, he incorrectly found the value of the median. He should not have included both 6 values, so the median is

At Step C, he incorrectly found the value of Q3. He should have included 10 to get Q3=14.At Step C, he incorrectly found the value of textsf cap q 3. He should have included 10 to get

At Step D, he incorrectly found the IQR. He should have found the difference between each quartile to get 10−6=4 and 15−10=5.At Step D, he incorrectly found the IQR. He should have found the difference between each quartile to get 10 minus 6 is equal to 4 and

He did not make a mistake.

Use the scenario to answer the question Bryan is asked to find the interquartile range for the data set 56681011141617 His work follows Step A Find the median o class=

Respuesta :

Given the steps used to calculate the interquartile range, Bryan did not make any mistake.

What is the interquartile range?

The interquartile range is the difference between the third quartile and the first quartile.

  • Third quartile = 3/4(n + 1) : 3/4 x 10 = 7.5 term : (14 + 16) / 2 = 15
  • First quartile = 1/4 x (n + 1) 1/4 x 10 = 2.5th term : (6 + 6) / 2 = 6
  • Interquartile range = 15 - 6 = 9

To learn more about interquartile range, please check:  https://brainly.com/question/3966385

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