The vessel's average speed for the entire journey will be 5.86 knots. The area of the distance-time graph shows the velocity.
Distance is a numerical representation of the distance between two objects or locations.
Distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.
The given data in the problem is;
Distance travelled 1 (D₁)= 6 nautical miles
Velocity (V₁) 8 knots.
Time (T₁)=
Distance travelled 2 (D₂)=5 nautical miles,
Time taken(T₂)=45 minutes=0.75 hour
Time taken(T₃)=30 minutes
Time for anchor 1 (t₁)=1 hour
Time for anchor 2(t₂)=0.5 hour
Time to sailing back to port(t₄) = 1 hour
The time for the first phase of motion;
[tex]\rm d = v\times t \\\\ t_1= \frac{D_1}{v} \\\\ t_1= \frac{6}{8} \\\\ t_1= 0.75 \ houe[/tex]
The average speed is found as;
[tex]\rm V_{avg}= \frac{Total \ distance }{Total \ time } \\\\ \rm V_{avg}= \frac{6+5+6+5}{0.75+0.5+1+0.5+1} \\\\ V_{avg}=5.866 \ knots[/tex]
Hence, the vessel's average speed for the entire journey will be 5.86 knots.
To learn more about the distance, refer to the link;
https://brainly.com/question/26711747
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