39200 mL of a 14.0 M [tex]HNO_3[/tex] solution should you use to make 840.0 mL of a 0.300 M [tex]HNO_3[/tex] solution.
The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilograms of carbon 12; its symbol is “mol”.
Solution:
[tex]M_1V_1 = M_2V_2[/tex]
In this case, [tex]M_1[/tex] = 840.0 mL, [tex]V_1[/tex]= 14.0 M , [tex]M_2[/tex]= 0.300 M
Substituting the value in the equation:
[tex]V_2[/tex] = [tex]\frac{840.0 X 14.0}{0.300}[/tex]
= 39200 mL
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