Respuesta :
Answer:
(2, 5 )
Step-by-step explanation:
3x + 2y = 16 → (1)
2x + y = 9 ( subtract 2x from both sides )
y = 9 - 2x → (2)
substitute y = 9 - 2x into (1)
3x + 2(9 - 2x) =16
3x + 18 - 4x = 16
- x + 18 = 16 ( subtract 18 from both sides )
- x = - 2 ( multiply both sides by - 1 )
x = 2
substitute x = 2 into (2)
y = 9 - 2(2) = 9 - 4 = 5
solution is (2, 5 )
multiplying eqn (1) by 2 and eqn (2) by 3 and substracting
6x+4y = 32
6x+3y = 27
we get,
y = 5
putting y = 5 in eqn (2) we get
2x + 5 =9
2x = 9 -5
2x = 4
or x = 2
therefore x = 2 and y =5.
(2,5)
6x+4y = 32
6x+3y = 27
we get,
y = 5
putting y = 5 in eqn (2) we get
2x + 5 =9
2x = 9 -5
2x = 4
or x = 2
therefore x = 2 and y =5.
(2,5)
