The initial value of the function is f(0) = 1 and the graph of the function has been attached.
We are given the function f(x) = (1/4)ˣ
1) Now, the initial value of the function is;
f(0) = (1/4)⁰ = 1
2) The initial value of the function which is the coordinate (0, 1) can be plotted on the attached graph and the point is where the graph crosses the y-axis.
3) f(1) = (1/4)¹ = 1/4
4) The points (1, 1/4) and (-1, 4)
5) The horizontal asymptote will be a vertical line which will be the value of x when y = 0.
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