[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$530000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years \end{cases} \\\\\\ A=530000\left(1+\frac{0.04}{4}\right)^{4\cdot t}\implies A=530000(1.01)^{4t} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\stackrel{\textit{after 12 years}}{t=12}\implies A=530000(1.01)^{4(12)}\implies A=530000(1.01)^{48} \\\\\\ A\approx 854479.82~\hfill \underset{\textit{interest in the account}}{\stackrel{854479.82~~ - ~~530000}{\approx 324479.82}}[/tex]
