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The interior of a refrigerator has a surface area of 2. 6 m2. It is insulated by a 4. 5 cm thick material that has a thermal conductivity of 0. 0098 J/m · s · ◦ C. The ratio of the heat extracted from the interior to the work done by the motor is 4. 4% of the theoretical maximum. The temperature of the room is 37. 7 ◦C, and the temperature inside the refrigerator is 3. 7 ◦C

Respuesta :

okpalawalter8

For an interior of a refrigerator has a surface area of 2. 6 m2, The power is  is mathematically given as

P= 71.56W

What is the power?

Generally, the equation for the  Fourier's law  is mathematically given as

H = ∆Q/∆t = k∙A∙∆T/∆x

Therefore

H= 0.0112* 4.2 *(33.3 - 6.8) / 0.022m

H= 58.18J/s

For The coefficient of performance(COP)

COP = Q/W = H/P

Therefore

COP = 279.95K/(306.45K - 279.95K)

COP = 10.564

In conclusion

P = H/COP

P= 58.18W / 0.813

P= 71.56W

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