samuelmeier187
contestada

13. A mass of 1 kg undergoes simple harmonic motion with amplitude of 1 m. If the period of the oscillation is 1 s, calculate the internal energy of the system.

Please show all of your work.

Respuesta :

first we need omega

  • T=1s

Hence

[tex]\\ \rm\rightarrowtail \omega=\dfrac{2\pi}{T}=2\pi[/tex]

Now

Total energy:-

[tex]\\ \rm\rightarrowtail \dfrac{1}{2}m\omega ^2A^2[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{1}{2}(1)(2\pi)^2(1)^2[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{1}{2}(4\pi ^2[/tex]

[tex]\\ \rm\rightarrowtail 2\pi ^2[/tex]

[tex]\\ \rm\rightarrowtail 2(3.14)^2[/tex]

[tex]\\ \rm\rightarrowtail 19.72J[/tex]

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